Quadratic Equations
A quadratic equation is a polynomial of degree 2 in the variable x:
ax2 + bx + c = 0 where a, b, c ∈ ℚ, a ≠ 0.
Terms: a — coefficient of x2, b — coefficient of x, c — constant term.
Example 1:
2x2 + 5x - 3 = 0 (standard form) — so a=2, b=5, c=-3.
2. Methods of Solving
A. Factorization
- Write
ax2 + bx + c = 0 - Factor into linear terms (if possible)
- Use zero-product property
Example: Solve
x2 - 5x + 6 = 0
(x - 2)(x - 3) = 0 ⇒ x = 2, 3B. Square Root Method
If the equation can be written x2 = k, then x = ±√k.
Example:
x2 = 16 ⇒ x = ±4C. Completing the Square
Rewrite to form a perfect square: (x + b/(2a))2 = (b2 - 4ac)/(4a2), then solve.
Example: Solve
x2 + 6x + 5 = 0
Complete square:
x2 + 6x + 9 = 4 ⇒ (x + 3)2 = 4 ⇒ x = -3 ± 2 → x = -1, -5D. Quadratic Formula
For ax2 + bx + c = 0:
x = (-b ± sqrt(b*b - 4*a*c)) / (2*a)
Example: Solve
2x2 - 4x - 6 = 0
Using formula:
x = (4 ± sqrt(16 + 48)) / 4 = (4 ± 8)/4 ⇒ x = 3, -13. Nature of Roots
The discriminant D = b2 - 4ac determines the nature:
| D | Nature | Example |
|---|---|---|
D > 0 | Two distinct real roots | x2 - 5x + 6 → 2, 3 |
D = 0 | Two equal real roots | x2 - 4x + 4 → 2, 2 |
D < 0 | No real roots (complex) | x2 + x + 1 |
4. Relationship Between Roots and Coefficients
If the roots are α and β for ax2 + bx + c = 0 then:
α + β = -b/aαβ = c/a
Example:
x2 - 7x + 12 = 0 → roots 3 & 4. Sum = 7, Product = 12.5. Forming Quadratics from Roots
Given roots α and β, an equation with leading coefficient 1 is:
x2 - (α + β)x + (αβ) = 0
Example: roots 5 and -2 ⇒
x2 - 3x - 10 = 06. Word Problems (brief)
- Area. Area of a square = 49 ⇒ side
x:x2=49⇒x=7(positive). - Motion. If a train takes 2 hours less at 5 km/h faster — leads to a quadratic in speed. (Set up: distances equal.)
- Mixture / Numbers. Two numbers with sum 10 and product 21 ⇒ equation
x2 - 10x + 21 = 0.
7. Quick Summary Table
| Concept | Formula / Method | Example |
|---|---|---|
| Standard Form | ax2+bx+c=0 | 2x2+5x-3=0 |
| Factorization | Factor & set each factor = 0 | x2-5x+6=(x-2)(x-3) |
| Square Roots | x2=k → x=±sqrt(k) | x2=16 → x=±4 |
| Completing Square | (x+b/2a)2=... | x2+6x+5→x=-1,-5 |
| Quadratic Formula | x=(-b±sqrt(b2-4ac))/(2a) | 2x2-4x-6 → 3,-1 |
8. Exercises
- Solve by factorization:
x2 - 3x - 10 = 0 - Solve by quadratic formula:
x2 + 5x + 6 = 0 - Solve by completing the square:
x2 + 6x + 5 = 0 - Find nature of roots:
2x2 - 4x + 2 = 0 - Form a quadratic equation whose roots are
4and-3.